The current schematic has two versions of the left and right
channel, with different parts values on it. These two standard
configurations have different benefits and problems:
These parts values are set up with bipolar-input chips in mind.
(All of the op-amps recommended on the parts list are bipolar.)
With this sort of chip, you have to worry about balancing the input
offset currents. If you don't want to cope with that, just use one
of the two standard configurations. Alternately, you can ignore the
input offset current issue by using a JFET-input op-amp, like the
AD8620. Unfortunately, it seems that all the good op-amps with high
output current abilities are bipolar-input. This is not to say
that an amp with relatively low output current abilities will sound
bad; many are happy with the standard CMoy
pocket amp configuration. I just ask that you consider what
you're giving up before making this choice.
If you want to change the gain or use a bipolar op-amp not
mentioned on the parts list, you will need to understand the issues
covered in the companion article Working with Cranky Op-Amps. Basically, the values
of the pot, C1, R2, R3 and R4 interact: changing one value often
requires changes to all the other values in order to maintain a
useful configuration.
C3 (C0G/NP0 ceramic)
These caps roll off the bandwidth of the left and right channels,
as explained in the Working with Cranky Op-Amps article. I recommend that you leave
these caps out until you determine that they are necessary.
R4 and C3 create a low-pass RC filter, whose corner
frequency is 1/(2*π*R4*C3). The corner frequency should be well
above the audio bandwidth, but if it's too high, it won't give a
useful effect. The corner frequency issue is why the schematic
recommends omitting C3 on the first page: with a 620 KΩ R4,
the smallest value you're going to be able to easily find for C3
(10 pF) results in a corner frequency that's too close to the
top of the audio band. R4 is much lower on the second page, so we
show a value for C3 there.
Do not use both C3 and L1 at the same time. They have
opposite effects. If you need L1, adding C3 will at least partially
defeat its purpose.
Optional? Yes. Do not jumper.
Largest Part Size: 1206 pacakge
C4 (electrolytic)
This is the main power reservoir capacitor, also called the "rail
capacitor" because it spans the power rails.
Use a 100 µF to 1000 µF capacitor with a voltage rating
higher than that of your power supply. For example, use a 25V capacitor
if your power supply is 24V.
I recommend the Panasonic FM, Panasonic FC, and Nichicon PW lines. The
Panasonic FC and the Nichicon PW are identical. The Panasonic FMs are
a little nicer than the FCs, but there are fewer values and fewer case
size choices in that line. If your chosen distributor doesn't carry
one of these lines, try to find a cap line that features long life and
low ESR.
If you want to choose your own power capacitors, there are two main
rules to keep in mind:
- Bigger is better, within a particular line of capacitors.
- It's usually better to use a lower-capacitance part from a
better line of capacitors than a higher-capacitance part from
a poorer-performing line of caps.
Sometimes you must compromise on quality (rule 2) to get a sufficient
amount of capacitance (rule 1). For a PINT, I recommend that you use
at least a 220 µF cap, and I'd much rather see something more
like 470 µF. If you're looking at caps over 1000 µF you're
probably compromising too much on quality; try looking for a line of
capacitors that will let you trade some of that excess capacitance for
higher quality. If you're already looking at the best capacitor line
available to you, you may simply choose not to buy that 2200 µF
capacitor, but instead get the 1000 µF one and save some money. I
doubt you can hear the difference.
Now to more specific advice.
First, decide on the capacitor's dimensions. For the cap to set down on
the board properly, the diameter needs to be 12.5mm or 10mm. The height
will be limited by the amount of space inside your case. You don't have
to use the tallest cap that will fit, you just need to keep this in mind
as a limit.
Next, you need to know your power supply
voltage. Your cap's voltage rating needs to be higher than your power
supply's maximum output voltage, but no higher than necessary to meet that
goal. For instance, if you have a 30V supply, 25V caps would be damaged
by the power supply, 35V caps are good, and 50V caps are wasteful. (For
more on this topic, read my article Op-Amp Working Voltage Considerations.)
Optional? No.
Largest Part Size: 12.5mm diameter
R1
This resistor sets the current used by the NiMH battery charging
circuit.
The formula for computing the proper resistor value is R=1.25÷I,
where I is the desired charging current. I recommend that you use the
standard trickle charge rate: 0.1 times your battery's mAh rating. (The
notation for that is "0.1C".) Since the default resistor value gives
a charging current of about 17 mA, it's suitable for NiMHs of 170 mAh
or higher.
Charging current is a trade-off between charge time and battery cycle
life. You can choose to charge faster than 0.1C, but your battery will
become useless after fewer charges than if you didn't abuse it so. If
you charge much greater than 0.1C, you must use some sort of intelligent
charger, which the PINT does not offer. Contrariwise, you can charge
slower than 0.1C to get more cycle life from your battery, but I wouldn't
go lower than 0.05C. Below that, the battery's self-discharge rate becomes
too significant: the battery won't charge as fast as it "should", and
it may actually fail to charge.
Optional? Yes. Leave it out.
Largest Part Size: 1206 package
R+, R-
These resistors divide the power supply voltage in half, setting the
virtual ground point.
Smaller values will lower the amp's noise floor. However, because this
divider is directly across the power rails, lowering these values wastes
more current. If you want to use a different value from the default,
you will have to trade off between noise and power supply drain.
Another concern is due to the current flowing in or out of U3A's
+IN input. This current goes across one of the two divider resistors,
pushing the divider's midpoint away from the centered ideal. The
largest bias current you'll see from any of the recommended op-amps
is 7 µA. (That's with the LM6172.) Following the standard rule of
thumb for this sort of thing, we must ensure that the current through
the divider is at least 10× the bias current. The lower the
supply voltage, the lower the current through the divider, so let's set
an arbitrary limit of 5 V. (That's near the clipping point for all of
the recommended chips with typical headphone loads.) At that voltage,
we can push over 70 µA through the divider if the resistors are
33 KΩ. (The formula is R=V÷140 µA, where R is the
resistor value, V is the supply voltage, and 140 µA is twice the
minumum divider current, since we're dealing with the midpiont of two
equal resistors in series.) The default value of 47 KΩ assumes that
you are either not using the "most biased" of the recommended op-amps,
or that if you are, you are not so exceptionally unlucky that it has
the worst-possible input bias current.
Optional? No.
Largest Part Size: 1206 package
L1
This position is for adding a part to increase the output
impedance, which can prevent oscillation with some op-amps. You can
put a resistor, a chip ferrite, or a chip inductor here.
If you need a part here to prevent oscillation and don't have
access to an oscilloscope, the safest path is to use a resistor in
this position. A value as low as 10 Ω will quell most oscillation
problems, but you may need to go up to as high as 100 Ω in
some situations. The lower the value, the better.
If you do have access to a scope, you can get better performance
from the amplifier by using a ferrite here instead. The reason is,
ferrites have low impedance at low frequencies, and rise in impedance
as frequency rises. This is exactly the behavior we want, because
we don't want any extra impedance at audio frequencies: we only
want it at high frequencies, where oscillation can occur. Just as
with the resistor, an impedance of between 10 Ω to 100 Ω
at the oscillation freqeuency will work best. But again, I must
stress that if you don't have an oscilloscope so you can determine
the oscillation frequency, you don't have enough information to
properly pick the right ferrite. Even then, it can take some trial
and error to find the right part.
You can use a chip inductor instead of a ferrite, but they have
higher DC resistances. I only mention this because it may be that
you cannot find a suitable ferrite, but you can find an inductor.
This is why L1 allows for 1210 size parts instead of 1206 like most
of the other passives: 1210 seems to be a more popular size for
chip inductors.
If it isn't needed to prevent oscillation, you can get better
performance by shorting this position by soldering a short length
of stiff wire across each position, such as trimmings from
C4's leads.
You should not use both L1 and C3 in the same
amplifier. Using one will at least partly cancel the effect of the
other. Some problems are best fixed by C3, others by L1.
Optional? Yes. Jumper it.
Largest Part Size: 1210 package
RLED
This is the LED current limiting resistor. Use Ohm's law to
figure the appropriate resistor value given the LED's voltage drop
(Vf), the power supply voltage (Vs) and the desired current
(I). For example, let's say the power supply voltage is 18V, and
we want 2 mA through our LED, which has a 1.8V forward voltage
drop:
R = (Vs - Vf) / I
R = (18 - 1.8) / 0.002
R = 16.2 / 0.002
R ~= 8.2 KΩ
Most LEDs require 1mA to get minimum acceptable brightness. More
current gets you more brightness, but of course uses more power, which
mainly matters with battery power supplies. You don't want the LED to
be too bright, because that's annoying.
Typical values are 1 KΩ to 10 KΩ. I personally use
2.2 KΩ and 4.7 KΩ most often.
Optional? Yes. Jumper only if your LED has an integral
resistor. Most don't.
Largest Part Size: 1206 package
Semiconductors
D1, D2
These diodes perform several interlocking functions.
In the simplest case, where you have just a single power supply,
you can use either D1 or D2 to provide reverse power supply voltage
protection. (Use D1 if your power supply's positive leg is connected to
the W+ pad, and D2 if it's connected to the B+ pad.) If you connect a
circuit like this up to a power supply and the voltages are backwards,
you'll blow up the op-amps almost instantly. That's a small price to
pay for 0.7 V or less of voltage loss.
If your amp can run from both a wall supply and batteries, the
situation is more complicated. In that case, you must have both diodes
installed. The first thing the two diodes do is form a diode OR bridge:
as long as the wall supply voltage is higher than the battery supply
voltage, plugging in the wall supply will stop the battery from running
the circuit, so the battery will charge. (The way this works is discussed
in the tweaks section
of my CMoy pocket amp assembly tutorial.) The second thing that happens
is that it prevents the battery from trying to run the wall supply
backwards, as well as preventing the wall supply from being connected
directly across the battery. Thirdly, you still get the reverse supply
protection mentioned above.
Optional? If using a single supply, one diode is optional, the
other is merely stronly recommended. If using batteries and wall power,
both diodes are mandatory.
Largest Part Size: S1A package
U1, U3
These two chips are dual-channel SO-8 op-amps. One chip handles
the left and right audio channels, and the other handles the input and
output halves of the virtual ground circuit. Some manufacturers make
chips in packages that aren't exactly SO-8, but are close enough to
work on the PINT, such as New Japan Radio's DMP-8 package.
The op-amps have the single biggest effect on sound and power draw
of any component, so it behooves you to pick these parts carefully.
The right and left channel op-amps do the actual amplification in the
PINT circuit. This should be the highest quality chip you can find, while
not going over your desired current budget. Unfortunately, it's generally
true that the higher the op-amp's quiescent current draw, the better it
will sound. The rule isn't infallible, but it's a good indicator.
There's a good argument that you should use the same chip for handling
ground as handles the output channels: the ground channel effectively
sits across the headphone from the left and right channels, so using
a matched circuit can result in more symmetric handling of the music,
resulting in less distortion.
In practice, however, there are a couple of good reasons to choose a
different op-amp for each position. First, mixing op-amp types can give
sonically interesting results. Second, mixing op-amps can allow you to
use a chip in the left and right channels that you would not want to use
in the ground channel for some reason, or vice versa. One such situation
is that the chip you're looking at for the left and right channel draws
too much current to use two of them. As long as you use a ground channel
chip capable of sinking enough current, it's okay to use a different
chip type here. Another situation is when you have a chip with input bias
currents so high that they cause too much DC offset in the left and right
channels. The ground channel is not nearly as susceptible to problems
from input bias currents, so such a chip could work just fine there.
Most any op-amp can be made to work in the PINT board, but some are
more suitable than others. Any FET-input op-amp should work on the board
without any trouble. If you use the resistor values on the schematic, any
bipolar input op-amp with a maximum input bias current in the low single
digit microamp range or lower should work fine. If it can have more than
a few microamps of bias current, you may have to choose different part
values to get DC offset down to acceptably low values.
The canonical part for this board is the AD8397, which is rebadged
as the AD45048. It has high output current, sounds great, runs to low
supply voltages, and will work from relatively high supply voltages. The
downside of the 8397 is that it drinks current like an Arizonan drinks
water after a bowl of hot chili. It's not uncommon for a PINT with a
pair of 8397s on it to draw over 50 mA! The longest lasting "9V" style
NiMH batteries you can buy today will only give you about 5 hours of
run time with this configuration.
If you need a longer run time than that, I recommend first replacing
just the ground channel op-amp. (U3) Try something like the LM6172,
or if the 12 V power supply limit isn't a problem, the LMH6643. (The
6172 will also work in U1, but the 6643 will not, due to its
high input bias currents. High bias currents don't matter as much in the
ground channel.) Not only will the amp run longer from your battery with
one of these chips in the ground channel, it's more likely to be stable,
as these chips are happier than the 8397 when running in unity gain.
Other suitable chips are recommended in the parts list.
For more details about op-amps, see the companion article,
Notes on Audio Op-Amps.
Optional? No.
Choosing a Power Supply
A power supply voltage somewhere in the 9 to 24V range will serve
you best. More voltage will probably hurt more than it helps, and lower
voltage will require very careful part choices to make a workable
amp. For a complete discussion on how to measure and calculate your
way to the ideal power supply voltage level for your situation, see my
article Op-Amp Working Voltage Considerations.
Battery Issues
If you're going to use batteries, it's simplest to put them all
in series. While you can parallel alkalines for longer battery life,
you should not do this with NiMHs, as stronger cells can easily damage
weaker ones in this configuration. (That doesn't happen with alkalines
partly because they aren't repeatedly stressed over long periods like
rechargeables are, and partly because the internal impedance of alkalines
is higher.) You should only use alkalines if your amp's power draw is
less than 30 mA or so. Otherwise, the battery will die prematurely.
The NiMH charging circuit (U2, R1,
D1 and D2) is a constant-current trickle
charger. NiMH manufacturers used to recommend removing the battery
from the charger as soon as it was done charging. That is not as big
a concern as it once was. Modern NiMH cells will withstand continuous
trickle charging for up to a year. While that's still not good for the
cells, don't worry if you leave the amp charging for a few days.
Wall Supply Issues
If you're going to use a wall power supply (a.k.a. "wall wart",
"AC/DC transformer"), there are a few different considerations with the
PINT.
First, if you want the wall supply to charge a NiMH battery,
its voltage should be at least 1.45× the number of cells
in the battery, plus 3 V to account for the drop across the
regulator. The 1.45 number is the peak voltage per
cell that you should see during charging. If you're using "9V" NiMHs,
divide the rated battery voltage by 1.2 to get the number of cells;
common configurations use anywhere from 6 to 8 cells. Let's say you're
using two 8.4 V NiMHs in series. Each one has 7 cells, so that's 14 in
total, giving a minimum charging voltage of 23.3 V. A 24 V supply would
be sufficient.
You also need to take care of the type of power supply you
use. The two words you need to look for are regulation and isolation.
An unregulated power supply's output voltage will fluctuate as the wall
voltage fluctuates. Also, unregulated power supplies tend to be cheap all
around, so they'll have a lot of ripple on their outputs. If you're just
using the wall supply to charge your battery, that's not a problem, but
it is if you're going to listen to the amp while it's on wall power. See
my Op-Amp Power Supply Quality Considerations article for the reasons why.
A regulated power supply's output will not fluctuate as the wall
power fluctuates, and they generally have much better N+R behavior
than cheap unregulated wall warts. Most power supplies that are simply
called "regulated" are in fact switching power supplies. These can have
more noise than unregulated supplies, because of the way they work. The
better type of regulation for audio is linear regulation. If it doesn't
say "linear regulated", assume it's a switcher. Regulated supplies are
best for audio, but are unnecessary if you're just using it to charge
the battery.
Your power supply also needs to be isolated, which means that the
output leads are not directly connected to any of the input leads. It's
common for non-isolated single-voltage supplies to tie their V- on the
DC output side to the earth ground connection on the AC side. Since the
PINT uses a "virtual ground", tying V- to earth ground can cause problems,
since this places the virtual ground several volts above earth ground. If
you plug the amp into a source component that uses earth ground for its
outputs, the amp's virtual ground will sit there fighting against the
source's true earth ground. The amp probably won't win that fight.
If you use an isolated supply, the amp's virtual ground can "float" to
whatever level is required by the source, and V+ and V- will float right
along with the virtual ground. Any supply with a transformer directly
between the AC side and the DC output (i.e. most linears and unregulated
supplies) is isolated. There are ways to make a switching power supply
isolated, but check to be sure: most switchers are not isolated, in my
experience. Because it's uncommon, if you have a switching power supply
that doesn't say that it's isolated, assume that it isn't.
If you can't get linear power supplies where you live, you can
make one easily enough by following an unregulated supply with a linear
regulation circuit. I offer the TREAD for that
purpose. Or, you can build a full-blown regulated wall power supply. You
can use the TREAD as part of that, or you can build the all-in-one STEPS power supply.
Choosing a Volume Control
The board has pads for the ALPS RK097 with the optional built-in
power switch. I offer the 10 KΩ version of this pot in my parts shop. If you're planning on getting an
"ALPS RK09" from somewhere else, be sure the part number begins with
RK097 or RK098. ALPS also has RK09D and RK09Ks, which are a completely
different physical design.
If you don't mind the extra work of hand-wiring a different pot to the
board, there are many other choices that will also work. There are a few
things you need to look for when choosing a pot. First, it needs to be a
dual-gang audio (or "log") taper pot. Second, it shouldn't be any lower
in value than 10 KΩ, or any higher than 100 KΩ. The lower the
better, generally, but 10 KΩ won't work well with some vintage audio
equipment, or tube equipment. 100 KΩ should work with anything, but
the higher the value, the more noise you get. Higher values also push up
the value of R2, and if you're using bipolar input op-amps,
that requires a cascade of other changes that usually won't work out in
the end.
Choosing an Enclosure
The standard PINT enclosure is a regular mint tin, such as an Altoids
or Penguin Mints tin. The board is designed to be just large enough
that you can just barely swing the board into position with the pot
attached. (That's why it doesn't actually go competely from front to
back in the tin.)
I expect that another popular enclosure will be the Hammond 1455C801.
The PINT board is just barely narrow enough to fit top-to-bottom in the
case and still leave enough room for a single 9V battery, a DC power
jack and the audio jacks. I haven't attempted this yet, though.
Because the PINT is so small, there are myriad other enclosures
you can use, from standard electronics project boxes and enclosures,
to found objects more creative than a mint tin.
If you want to use a metal enclosure, read the next few sections,
as this affects which panel components will work.
Choosing the Audio Jacks
If you're using a metal case, at least one of the audio jacks needs
to be isolated from the case. Isolation, in this instance, means that
none of the audio signals are connected to any metal parts of the jack
that touch the mounting surface. Usually, this means the jack body and
mounting threads are plastic, but not always. The most common way for
a jack to be non-isolated is to have a metal shell that's connected to
the ground signal.
It's okay if either input or output ground connects to the enclosure,
but if both do, the ground channel will be shorted out. At best, this
makes the ground channel useless, and at worst it can cause the amp to
become unstable. If you're going to connect one of the grounds to the
case, it should be the input ground.
The easiest type of jack to deal with is fully isolated, which some
of those mentioned in the parts list are. Again, this usually means that
the jack is mostly plastic. This can indicate a lower quality jack, so
there's some incentive to put up with the problems you get by choosing
a different type.
Some jacks have plastic mounting threads but have a metal tab connected
to ground that touches the inside mounting surface. These can be made
isolated simply by adding a plastic washer around the jack's snout before
mounting it.
If the jack's threads are metal, you can still isolate the jack from
the case by using shoulder washers, but finding or making them in the
proper size isn't easy.
If your amp will use a DC power jack, read on. The isolation issue
gets more complicated in that instance.
Choosing a Power Input Jack
If you are using a metal case and you will be adding a DC power jack
to your amp, you have a similar isolation issue as brought up for the
audio jacks. A metal bodied DC jack usually has no isolation between the
barrel of the plug and the jack body. Therefore, using such a jack with
a tip-positive power supply would tie the case to V- when the supply
is plugged in. That's hardly the worst thing in the world from an EMI
shielding perspective, but if both of the audio jacks aren't isolated,
this will tie V- to virtual ground, which will collapse the virtual
ground.
You have three choices: 1) use an isolated power jack; 2) isolate
your audio jacks; or 3) don't use a metal case.
In my recent builds in mint tins, I've been using a non-isolated
DC power jack and isolating the audio jacks. The reason for this is
complicated. First, the only isolated DC jack I'm aware of is too big to
fit on the side of a mint tin without hackery. Second, while I could use
a more compact metal bodied jack and isolate it, I don't have the proper
shoulder washers for this. Third, I'm not dogmatic about tying V- to the
case instead of input ground; some people insist that this is evil.
Speaking of fitting jacks on the side of mint tins: only the one marked
"compact" in the parts list is small enough for this. The others could
be made to fit, either by grinding down the mounting flanges so the lid
can close, or by cutting a notch in the mint tin lid's edge.